derivative of -3cos^2(x)
Let's differentiate: ddx(-3·cos(x)2)
We differentiate using: ddx(fn) = n·ddx(f)·fn -1 (where f = cos(x))
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(-3·cos(x)2) = -3·ddx(cos(x)2)■The derivative of x^n is n*x^(n-1): ddx(cos(x)2) = 2·ddx(cos(x))·cos(x)
-3·2·ddx(cos(x))·cos(x)
ⓘ The derivative of cos(x) is -sin(x): ddx(cos(x)) = -sin(x)
ⅰ 3·2 = 6
-6·(-sin(x))·cos(x)
ⓘ Two minus signs cancel out: -6·(-sin(x)) = 6·sin(x)
6·sin(x)·cos(x)
▶Derivative:   6·cos(x)·sin(x)