derivative of (5x^3+7x^2/x)
Let's perform the differentiation: ddx(5x3 + 7x2x)
ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor: 7x2x = 7x
ddx(5x3 + 7x)
ⓘ The derivative of a sum is the sum of the derivatives: ddx(5x3 + 7x) = ddx(5x3) + ddx(7x)
ddx(5x3) + ddx(7x)
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(5x3) = 5·ddx(x3), ddx(7x) = 7■The derivative of x^n is n*x^(n-1): ddx(x3) = 3x2
5·3x2 + 7
ⓘ Multiplications are done before additions and subtractions: 5·3 = 15
▶Derivative:   15x2 + 7