derivative of (sin(x)/(x^2))
1) Let's perform the differentiation: ddx(sin(x)x2)
For p1 = sin(x) and q2 = x2, use the differentiation rule: ddx(p1q2) = ddx(p1)·q2 -p1·ddx(q2)q22
2) Let's perform the differentiation p1: ddx(sin(x))
ⓘ The derivative of sin(x) is cos(x): ddx(sin(x)) = cos(x)
cos(x)
3) Let's differentiate q2: ddx(x2)
ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
2x
4) We evaluate the resulting derivative (p1q2)': cos(x)·x2 -sin(x)·2x(x2)2
ⓘ What the terms have in common is factored out, so that the fraction can be simplified: cos(x)·x2 -sin(x)·2x(x2)2 = x·(x·cos(x) -2·sin(x))(x2)2■A power of a power multiplies the exponents, (a^n)^m = a^(n*m): (x2)2 = x2·2
x·(x·cos(x) -2·sin(x))x2·2
ⅰ 2·2 = 4
x·(x·cos(x) -2·sin(x))x4
We simplify the fraction: xx4 by the common factor: x to get the new quotient: 1x3
x·cos(x) -2·sin(x)x3
5) Then you can continue the differentiation:
ⅰ ddx(sin(x)x2) = x·cos(x) -2·sin(x)x3
▶Derivative:   x·cos(x) -2·sin(x)x3