derivative of (tan^3(x)/3)
Let's differentiate: ddx(tan(x)33)
We differentiate using: ddx(fn) = n·ddx(f)·fn -1 (where f = tan(x))
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u'. The derivative of x^n is n*x^(n-1): ddx(tan(x)33) = 13·3·ddx(tan(x))·tan(x)2
13·3·ddx(tan(x))·tan(x)2
ⓘ Multiplying by 1 changes nothing: 1·ddx(tan(x))·tan(x)2 = ddx(tan(x))·tan(x)2
ⅰ 13·3 = 1
ddx(tan(x))·tan(x)2
ⓘ The derivative of tan(x) is 1/cos(x)^2: ddx(tan(x)) = 1cos(x)2
1cos(x)2·tan(x)2
▶Derivative:   tan(x)2cos(x)2