derivative of sin(arctan(3x))
Let's differentiate: ddx(sin(arctan(3x)))
Apply the differentiation rule: ddx(sin(f)) = ddx(f)·cos(f) with f = arctan(3x)
ⓘ The derivative of sin(x) is cos(x): ddx(sin(arctan(3x))) = ddx(arctan(3x))·cos(arctan(3x))
ddx(arctan(3x))·cos(arctan(3x))
For real t, arctan(t) lies in (−π/2, π/2), so its cosine is positive and cos(arctan(t)) = 11 + t2
ⅰ cos(arctan(3x)) = 11 + (3x)2
ddx(arctan(3x))·11 + (3x)2
Apply the differentiation rule: ddx(arctan(f)) = ddx(f)·1f2 + 1 with f = 3x
ⓘ The derivative of arctan(x) is 1/(1 + x^2): ddx(arctan(3x)) = ddx(3x)(3x)2 + 1
ddx(3x)(3x)2 + 1·11 + (3x)2
ⓘ To multiply fractions, multiply the numerators together and the denominators together: ddx(3x)(3x)2 + 1·11 + (3x)2 = ddx(3x)·1((3x)2 + 1)·1 + (3x)2 = ddx(3x)((3x)2 + 1)·1 + (3x)2■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(3x) = 3■Multiplying powers with the same base adds the exponents: ((3x)2 + 1)·1 + (3x)2 = ((3x)2 + 1)1 + 12
3((3x)2 + 1)1 + 12
ⓘ To add fractions, put them over the same denominator, then add the numerators: 1 + 12 = 2 + 12
3((3x)2 + 1)2 + 12
ⓘ The numerator and the denominator are computed before the division: 2 + 1 = 3
3((3x)2 + 1)32
ⓘ The power of a product is the product of the powers: (3x)2 = 32·x2
3(32·x2 + 1)32
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 32 = 3·3 = 9
▶Derivative:   3(9x2 + 1)32