derivative of sqrt(2-3x^2)
Let's differentiate: ddx(2 -3x2)
We differentiate using: ddx(f) = ddx(f)·12f (where f = 2 -3x2)
ⓘ The derivative of sqrt(x) is 1/(2*sqrt(x)): ddx(2 -3x2) = ddx(2 -3x2)·12·2 -3x2
ddx(2 -3x2)·12·2 -3x2
ⓘ Multiplying a fraction by a term multiplies its numerator: ddx(2 -3x2)·12·2 -3x2 = ddx(2 -3x2)·12·2 -3x2 = ddx(2 -3x2)2·2 -3x2■The derivative of a sum is the sum of the derivatives: ddx(2 -3x2) = 0 + ddx(-3x2)
0 + ddx(-3x2)2·2 -3x2
ⓘ Adding 0 changes nothing: 0 + ddx(-3x2) = ddx(-3x2)■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(-3x2) = -3·ddx(x2)■The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
-3·2x2·2 -3x2
ⅰ 3·2 = 6
-6x2·2 -3x2
-6x2·2 -3x2
ⓘ A fraction is simplified by dividing the numerator and the denominator by the same number: -6x2·2 -3x2 = -3x2 -3x2
▶Derivative:   -3x2 -3x2