derivative of x^3csc(x)
1) Let's perform the differentiation: ddx(x3·csc(x))
For u1 = x3 and v2 = csc(x), use the differentiation rule: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
2) Let's differentiate u1: ddx(x3)
ⓘ The derivative of x^n is n*x^(n-1): ddx(x3) = 3x2
3x2
3) Let's perform the differentiation v2: ddx(csc(x))
ⓘ The derivative of csc(x) is -csc(x)*cot(x): ddx(csc(x)) = -csc(x)·cot(x)
-csc(x)·cot(x)
4) Let's evaluate the resulting derivative (u1·v2)': 3x2·csc(x) + x3·(-csc(x)·cot(x))
ⓘ The minus sign is placed in front of the product: x3·(-csc(x)) = -x3·csc(x)
3x2·csc(x) -x3·csc(x)·cot(x)
5) You can then resume the differentiation:
ⅰ ddx(x3·csc(x)) = 3x2·csc(x) -x3·csc(x)·cot(x)
3x2·csc(x) -x3·csc(x)·cot(x)
3x2·csc(x) -x3·cot(x)·csc(x)
x2·csc(x)·(3 -x·cot(x))
▶Derivative:   x2·csc(x)·(3 -x·cot(x))