differentiate ln(x^2+4) — step-by-step solution

Let's perform the differentiation:

{(\ln (x^{2} + 4))}^{'}

Apply the differentiation rule:

{(\ln (f))}^{'} = {(f)}^{'} \cdot \frac{1}{f}

with f =

x^{2} + 4

{(x^{2} + 4)}^{'} \cdot \frac{1}{x^{2} + 4}

ℹ

(x^2+4)' \cdot \frac{1}{x^{2} + 4}

\frac{(x^2+4)'}{x^{2} + 4}

‖

(x^2+4)'

(x^2)' + 0

\frac{{(x^{2})}^{'} + 0}{x^{2} + 4}

▷Result: $\frac{2 x}{x^{2} + 4}$