differentiate (x-2)^3
Let's differentiate: ddx((x -2)3)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = x -2
ⓘ The derivative of x^n is n*x^(n-1): ddx((x -2)3) = 3·ddx(x -2)·(x -2)2
3·ddx(x -2)·(x -2)2
ⓘ The derivative of a sum is the sum of the derivatives: ddx(x -2) = 1 + 0
3·(1 + 0)·(x -2)2
ⓘ Adding 0 changes nothing: 1 + 0 = 1
▶Derivative:   3·(x -2)2