Let's differentiate: ((x -2)3)' Apply the differentiation rule: (fn)' = n·(f)'·f(n -1) with f = x -2 3·(x -2)'·(x -2)2 ℹ(x+-2)' = 1 + 0 3·(1 + 0)·(x -2)2 ▷Answer: 3·(x -2)2