differentiate (x-2)^3
Let's differentiate: ((x -2)3)'
Apply the differentiation rule: (fn)' = n·(f)'·f(n -1) with f = x -2
3·(x -2)'·(x -2)2
(x+-2)' = 1 + 0
3·(1 + 0)·(x -2)2
Answer:   3·(x -2)2