differentiate (x+1)^2
Let's differentiate: ddx((x + 1)2)
Apply the differentiation rule: ddx(fn) = n·ddx(f)·fn -1 with f = x + 1
ⓘ The derivative of x^n is n*x^(n-1): ddx((x + 1)2) = 2·ddx(x + 1)·(x + 1)
2·ddx(x + 1)·(x + 1)
ⓘ The derivative of a sum is the sum of the derivatives: ddx(x + 1) = 1 + 0
2·(1 + 0)·(x + 1)
ⓘ Adding 0 changes nothing: 1 + 0 = 1
▶Derivative:   2·(x + 1)