Let's perform the differentiation: ((x + 1)2)' Apply the differentiation rule: (fn)' = n·(f)'·f(n -1) with f = x + 1 2·(x + 1)'·(x + 1) ℹ(x+1)' = 1 + 0 2·(1 + 0)·(x + 1) ▷Result: 2·(x + 1)