differentiate (x^2+1)^3
Let's perform the differentiation: ddx((x2 + 1)3)
We differentiate using: ddx(fn) = n·ddx(f)·fn -1 (where f = x2 + 1)
ⓘ The derivative of xn is nxn -1: ddx((x2 + 1)3) = 3·ddx(x2 + 1)·(x2 + 1)2
3·ddx(x2 + 1)·(x2 + 1)2
ⓘ The derivative of a sum is the sum of the derivatives: ddx(x2 + 1) = ddx(x2) + 0
3·(ddx(x2) + 0)·(x2 + 1)2
ⓘ Adding 0 changes nothing: ddx(x2) + 0 = ddx(x2)■Differentiating xn gives nxn -1: ddx(x2) = 2x
3·2x·(x2 + 1)2
ⅰ 3·2 = 6
▶Derivative:   6x·(x2 + 1)2