differentiate sin(3x) — step-by-step solution

Let's differentiate:

{(\sin (3 x))}^{'}

We differentiate using:

{(\sin (f))}^{'} = {(f)}^{'} \cdot \cos (f)

(where f =

3 x

)

{(3 x)}^{'} \cdot \cos (3 x)

▷Result: $3 \cdot \cos (3 x)$