differentiate sqrt(4x+1) — step-by-step solution

Let's differentiate:

{(\sqrt{4 x + 1})}^{'}

We differentiate using:

{(\sqrt{f})}^{'} = {(f)}^{'} \cdot \frac{1}{2 \sqrt{f}}

(where f =

4 x + 1

)

{(4 x + 1)}^{'} \cdot \frac{1}{2 \cdot \sqrt{4 x + 1}}

ℹ

(4*x+1)' \cdot \frac{1}{2 \cdot \sqrt{4 x + 1}}

\frac{(4*x+1)'}{2 \cdot \sqrt{4 x + 1}}

‖

(4*x+1)'

(4*x)' + 0

\frac{{(4 x)}^{'} + 0}{2 \cdot \sqrt{4 x + 1}}

ℹ

(4*x)' + 0

(4*x)'

‖

(4*x)'

4

\frac{4}{2 \cdot \sqrt{4 x + 1}}

▷Result: $\frac{2}{\sqrt{4 x + 1}}$