Let's differentiate: (x2ex)' We differentiate U1 = x2 and V2 = ex using: (U1·V2)' = (U1)'·V2 + U1·(V2)' Let's differentiate U1: (x2)' 2x Let's perform the differentiation V2: (ex)' ex Then you can resume the differentiation: 2xex + x2ex exx2 + 2exx You can factorize this expression into: exx·(x + 2) ▷Answer: exx·(x + 2)