differentiate x^2*e^x
Let's differentiate: ddx(x2ex)
For u1 = x2 and v2 = ex, use the differentiation rule: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
Let's perform the differentiation u1: ddx(x2)
ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
2x
Let's differentiate v2: ddx(ex)
ⓘ The derivative of exp(x) is exp(x): ddx(ex) = ex
ex
Then you can resume the derivation:
ⅰ ddx(x2ex) = 2xex + x2ex
2xex + x2ex
exx2 + 2exx
exx·(x + 2)
▶Derivative:   exx·(x + 2)