differentiate x^3*e^x
Let's differentiate: ddx(x3ex)
For u1 = x3 and v2 = ex, use the differentiation rule: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
Let's perform the differentiation u1: ddx(x3)
ⓘ The derivative of xn is nxn -1: ddx(x3) = 3x2
3x2
Let's perform the differentiation v2: ddx(ex)
ⓘ Differentiating exp(x) gives exp(x): ddx(ex) = ex
ex
Then you can resume the differentiation:
ⅰ ddx(x3ex) = 3x2ex + x3ex
3x2ex + x3ex
exx3 + 3exx2
exx2·(x + 3)
▶Derivative:   exx2·(x + 3)