differentiate x^3*e^x
Let's perform the differentiation: (x3ex)'
For U1 = x3 and V2 = ex, use the product/quotient rule: (U1·V2)' = (U1)'·V2 + U1·(V2)'
Let's differentiate U1: (x3)'
3x2
Let's differentiate V2: (ex)'
ex
Then you can continue the differentiation:
3x2ex + x3ex
exx3 + 3exx2
This expression can be factorized into: exx2·(x + 3)
Result:   exx2·(x + 3)