Let's perform the differentiation: (x3ex)' For U1 = x3 and V2 = ex, use the product/quotient rule: (U1·V2)' = (U1)'·V2 + U1·(V2)' Let's differentiate U1: (x3)' 3x2 Let's differentiate V2: (ex)' ex Then you can continue the differentiation: 3x2ex + x3ex exx3 + 3exx2 This expression can be factorized into: exx2·(x + 3) ▷Result: exx2·(x + 3)