differentiate x^5 twice
1) Let's perform the differentiation: ddx(x5)
ⓘ The derivative of x^n is n*x^(n-1): ddx(x5) = 5x4
5x4
2) Let's differentiate: ddx(5x4)
ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(5x4) = 5·ddx(x4)■The derivative of x^n is n*x^(n-1): ddx(x4) = 4x3
5·4x3
ⅰ 5·4 = 20
▶Derivative:   20x3