differentiate x*e^x
1) Let's perform the differentiation: ddx(xex)
For u1 = x and v2 = ex, use the differentiation rule: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
2) Let's differentiate u1: ddx(x)
ⓘ The derivative of x is 1: ddx(x) = 1
1
3) Let's perform the differentiation v2: ddx(ex)
ⓘ The derivative of exp(x) is exp(x): ddx(ex) = ex
ex
4) Let's evaluate the resulting derivative (u1·v2)': 1·ex + xex
ex + xex
5) Then you can continue the derivation:
ⅰ ddx(xex) = ex + xex
ex + xex
exx + ex
ex·(x + 1)
▶Derivative:   ex·(x + 1)