differentiate x*ln(x)
Let's perform the differentiation: ddx(x·ln(x))
For u1 = x and v2 = ln(x), use the differentiation rule: ddx(u1·v2) = ddx(u1)·v2 + u1·ddx(v2)
Let's differentiate u1: ddx(x)
ⓘ The derivative of x is 1: ddx(x) = 1
1
Let's perform the differentiation v2: ddx(ln(x))
ⓘ The derivative of ln(x) is 1/x: ddx(ln(x)) = 1x
1x
Let's evaluate the resulting derivative (u1·v2)': 1·ln(x) + x·1x
ⓘ Multiplying a fraction by a term multiplies its numerator: x·1x = x·1x = xx■The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor x: xx = 1
ⅰ ddx(x·ln(x)) = ln(x) + 1
▶Derivative:   ln(x) + 1