differentiate x*ln(x)
Let's perform the differentiation: (x·ln(x))'
We differentiate U1 = x and V2 = ln(x) using: (U1·V2)' = (U1)'·V2 + U1·(V2)'
Let's perform the differentiation U1: (x)'
1
Let's differentiate V2: (ln(x))'
1x
You can evaluate the resulted derivative (U1·V2)': 1·ln(x) + x·1x
Answer:   ln(x) + 1