domain of f(x)=ln(9x^2+1) — step-by-step solution

We save the definition:

f (x) = \ln (9 x^{2} + 1)

Let's evaluate the domain of

\ln (9 x^{2} + 1)

For the expression

\ln (9 x^{2} + 1)

to be defined, we must have:

9 x^{2} + 1 > 0

The condition

9 x^{2} + 1 > 0

is always true on its real domain

ⓘ This expression imposes no restriction on the real variable

▶Domain of definition:

x \in ℝ