domain of f(x)=(2x-16)/(x^2-16x)

We save the definition:

f (x) = \frac{2 x - 16}{x^{2} - 16 x}

Let's evaluate the domain of

\frac{2 x - 16}{x^{2} - 16 x}

For the expression

\frac{2 x - 16}{x^{2} - 16 x}

to be defined, we must have:

x^{2} - 16 x \neq 0

You can factor:

x^{2} - 16 x

into:

x \cdot (x - 16)

⇥Let's solve in

ℝ

x \neq 0

⇥Solution obtained:

x \neq 0

⇥Let's solve in

ℝ

x - 16 \neq 0

⇥Solution found:

x \neq 16

▶Domain of definition:

x \in ℝ \ {0, 16}