domain of f(x)=(x+7)/(x^2-14x+49)

We save the definition:

f (x) = \frac{x + 7}{x^{2} - 14 x + 49}

Let's find the domain of

\frac{x + 7}{x^{2} - 14 x + 49}

For the expression

\frac{x + 7}{x^{2} - 14 x + 49}

to exist, you must check:

x^{2} - 14 x + 49 \neq 0

You can transform this expression into:

{(x - 7)}^{2}

{(x - 7)}^{2} \neq 0

means that:

x - 7 \neq 0

ⓘ We add

7

to both sides

▶Domain of definition:

x \neq 7