domain of f(x)=sqrt(3-6x)
We save the definition: f(x) = 3 -6x
Let's evaluate the domain of 3 -6x
For the expression 3 -6x to be defined, we must have: 3 -6x ≥ 0
ⓘ We add 6x to both sides
3 ≥ 6x
ⓘ Both sides are divided by 6
x ≤ 36
ⓘ We simplify the fraction by dividing the numerator and the denominator by 3, their greatest common divisor: 36 = 1·32·3 = 12
▶Domain of definition:   x ≤ 12
The numeric value of: x ≤ 12 is:
▷ x ≤ 0.5