domain of g(x)=(2x)/(x^2-9) — step-by-step solution

We save the definition:

g (x) = \frac{2 x}{x^{2} - 9}

Let's find the domain of

\frac{2 x}{x^{2} - 9}

For the expression

\frac{2 x}{x^{2} - 9}

to be defined, we must have:

x^{2} - 9 \neq 0

The two numbers whose square is

9

are

-3

and

3

▶Domain of definition:

x \in ℝ \ {-3, 3}