domain of (2x^2)/(3x+2)
Let's find the domain of 2x23x + 2
For the expression 2x23x + 2 to exist, you must check: 3x + 2 ≠ 0
ⓘ We subtract 2 from both sides
3x ≠ -2
ⓘ Both sides are divided by 3
▶Domain of definition:   x ≠ -23
The numeric value of: x ≠ -23 equals:
▷ x ≠ -0.6667 (approximate value)