Let's expand: (2x + 1)2 (2x + 1)·(2x + 1) 2·x·2·x + 2x·1 + 1·2x + 1·1 ℹ2·2 = 4‖x·x = x2‖2x·1 = 2x‖1·2x = 2x‖1·1 = 1 4x2 + 2x + 2x + 1 ▷Result: 4x2 + 4x + 1