Let's write in expanded form: $(x-2)·(x-3)$

ⓘ Expand by multiplying each term inside the parentheses: $(x-2)·(x-3)$ = $x·x$$+x·\left(-3\right)$$-2x$$-2·\left(-3\right)$

$x·x$$+x·\left(-3\right)$$-2x$$-2·\left(-3\right)$

ⓘ Multiplying powers with the same base adds the exponents: $x·x$ = $x^2$■The minus sign is placed in front of the product: $x·\left(-3\right)$ = $-3x$■Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: $-2·\left(-3\right)$ = $6$

$x^2$$-3x$$-2x$$+6$

ⓘ Like terms are grouped by adding their coefficients: $-3x-2x$ = $-5x$

▶Expanded form:   $x^2-5x+6$