Let's expand: (x + 5)·(x -5) x·x + x·-5 + 5x + 5·-5 ℹx·x = x2‖x·-5 = -x·5‖5·-5 = -25 x2 -x·5 + 5x -25 ℹ-x·5 + 5x = 0 x2 + 0 -25 ▷Result: x2 -25