extreme x^2+2x+3
1) Find the strict local extrema of x2 + 2x + 3 on ℝ: the derivative must be zero and change sign
⇥1.1) Let's differentiate: ddx(x2 + 2x + 3)
⇥ⓘ The derivative of a sum is the sum of the derivatives: ddx(x2 + 2x + 3) = ddx(x2) + ddx(2x) + 0
⇥ ddx(x2) + ddx(2x) + 0
⇥ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x■Adding 0 changes nothing: ddx(2x) + 0 = ddx(2x)■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(2x) = 2
⇥ 2x + 2
⇥The first derivative is 2x + 2
⇥1.2) Let's solve in ℝ: 2x + 2 = 0
⇥ⓘ We subtract 2 from both sides
⇥ 2x = -2
⇥ⓘ Both sides are divided by 2
⇥ x = -22
⇥ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: -22 = -1
⇥Solution found: x = -1
⇥1.3) Let's differentiate: ddx(2x + 2)
⇥ⓘ The derivative of a sum is the sum of the derivatives: ddx(2x + 2) = ddx(2x) + 0
⇥ ddx(2x) + 0
⇥ⓘ Adding 0 changes nothing: ddx(2x) + 0 = ddx(2x)■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(2x) = 2
⇥ 2
⇥The second derivative is 2
2) At x = -1, calculate f''(-1) = 2
At x = -1, the second derivative is positive: this is a strict local minimum
⇥ (-1)2 + 2·(-1) + 3
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-1)2 = (-1)·(-1) = 1■Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 2·(-1) = -2
⇥ 1 -2 + 3
⇥ⓘ Start from 1 and move back 2 on the number line, going below zero: 1 -2 = -1
⇥ -1 + 3
⇥ⓘ Start from -1 and move forward 3 on the number line, going past zero: -1 + 3 = 2
⇥ 2
The y-coordinate is f(-1) = 2
▶Strict local extrema:   {(-1, 2)}