factor 11x^3+125x^2+45x+11
1) Let's factorize in ℝ: 11x3 + 125x2 + 45x + 11
⇥1.1) Try the obvious solution first: x = -11
⇥Let's evaluate the value of: 11·(-11)3 + 125·(-11)2 + 45·(-11) + 11
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-11)3 = (-11)·(-11)·(-11) = -1331, (-11)2 = (-11)·(-11) = 121■Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 45·(-11) = -45·11 = -45·(10 + 1) = -(45·10 + 45) = -(450 + 45) = -495
⇥ 11·(-1331) + 125·121 -495 + 11
⇥ⓘ Multiplications are done before additions and subtractions. A single minus sign does not cancel out, the product of a negative number by a positive number is negative: 11·(-1331) = -11·1331 = -(10 + 1)·1331 = -(10·1331 + 1331) = -(13,310 + 1331) = -14,641■Multiplications are done before additions and subtractions: 125·121 = 125·(100 + 20 + 1) = 125·100 + 125·20 + 125 = 12,500 + 2500 + 125 = 15,125■Start from -495 and move forward 11 on the number line, getting closer to zero: -495 + 11 = -484
⇥ -14,641 + 15,125 -484
⇥ⓘ Start from -14,641 and move forward 15,125 on the number line, going past zero: -14,641 + 15,125 = 484
⇥ 484 -484
⇥ⓘ Start from 484 and move back 484 on the number line, down to zero: 484 -484 = 0
⇥ 0
⇥Root found: x = -11
⇥1.2) Compute the quotient and remainder of (11x3 + 125x2 + 45x + 11) ÷ (x + 11)
⇥
Expression in progressDivide
leading terms
QuotientQuotient × divisorRemainder after subtracting
11x3 + 125x2 + 45x + 1111x3x11x211x2·(x + 11) = 11x3 + 121x2(11x3 + 125x2 + 45x + 11) -(11x3 + 121x2) = 4x2 + 45x + 11
4x2 + 45x + 114x2x4x4x·(x + 11) = 4x2 + 44x(4x2 + 45x + 11) -(4x2 + 44x) = x + 11
x + 11xx1x + 11 = x + 11(x + 11) -(x + 11) = 0
⇥Therefore, the result of the euclidean division is: 11x2 + 4x + 1
ⅰ 11x3 + 125x2 + 45x + 11 = (x + 11)·(11x2 + 4x + 1)
▶Factored expression:   (x + 11)·(11x2 + 4x + 1)