factor 3m^2+6m+3
Let's factorize in ℝ: 3m2 + 6m + 3
We factor out 3, the greatest common divisor of the coefficients: 3m2 + 6m + 3 = 3·(m2 + 2m + 1)
Recognize the square of a sum: a2 + 2ab + b2 = (a + b)2, with a = m and b = 1; the cross term is 2m = 2m
Factor identified: (m + 1)2
▶Factored expression:   3·(m + 1)2