factor 4x^3-32
1) Let's factor in ℝ: 4x3 -32
We factor out 4, the greatest common divisor of the coefficients: 4x3 -32 = 4·(x3 -8)
⇥1.1) The roots of x3 -8 are the solutions of x3 = 8
⇥The (complex) solutions are: 83·exp(i·2kπ3) for k from 0 to 2
⇥
kExponential solutionTransformed and simplified as
02exp(i·2·0·π3) = 22·(cos(0) + i·sin(0)) = 2
12exp(i·2·1·π3) = 2exp(i·2π3)2·(cos(2π3) + i·sin(2π3)) = -1 + i·3
22exp(i·2·2·π3) = 2exp(i·4π3)2·(cos(4π3) + i·sin(4π3)) = -1 -i·3
⇥The factorization for the real solution(s) yields: x -2
⇥1.2) Perform polynomial long division of (x3 -8) by (x -2)
⇥
Current expressionDivide
leading terms
QuotientQuotient × divisorRemainder after subtracting
x3 -8x3xx2x2·(x -2) = x3 -2x2(x3 -8) -(x3 -2x2) = 2x2 -8
2x2 -82x2x2x2x·(x -2) = 2x2 -4x(2x2 -8) -(2x2 -4x) = 4x -8
4x -84xx44·(x -2) = 4x -8(4x -8) -(4x -8) = 0
⇥So the result of the euclidean division is: x2 + 2x + 4
ⓘ The other roots, -1 -i·3, -1 + i·3, are not real: x2 + 2x + 4 cannot be factored in ℝ
Factors identified: (x -2)·(x2 + 2x + 4)
▶Factored expression:   4·(x -2)·(x2 + 2x + 4)