factor 56x^2+31x+3
Let's factor in ℝ: 56x2 + 31x + 3
Given the quadratic form ax2 + bx + c, let's compute the discriminant: Δ = b2 -4ac. Here a = 56, b = 31 and c = 3
Δ = 312 -4·56·3
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 312 = 31·31 = 961■Multiplications are done before additions and subtractions: 4·56 = 4·(50 + 6) = 4·50 + 4·6 = 200 + 24 = 224
Δ = 961 -224·3
ⓘ Multiplications are done before additions and subtractions: 224·3 = (200 + 20 + 4)·3 = 200·3 + 20·3 + 4·3 = 600 + 60 + 12 = 672
Δ = 961 -672
ⓘ Start from 961 and move back 672 on the number line: 961 -672 = 289
Δ = 289
As Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -31 -2892·56
x1 = -31 -2892·56
ⓘ The square root of a number is the positive number whose square is that number: 289 = 17; 172 = 289
ⅰ 2·56 = 2·(50 + 6) = 2·50 + 2·6 = 100 + 12 = 112
x1 = -31 -17112
ⓘ The numerator and the denominator are computed before the division: -31 -17 = -48
x1 = -48112
We simplify the fraction: 48112 by the common factor: 16 to get the new fraction: 37
x1 = -37
The quadratic formula gives x2 = -b + Δ2a = -31 + 2892·56
x2 = -31 + 2892·56
ⓘ The square root of a number is the positive number whose square is that number: 289 = 17; 172 = 289
ⅰ 2·56 = 2·(50 + 6) = 2·50 + 2·6 = 100 + 12 = 112
x2 = -31 + 17112
ⓘ The numerator and the denominator are computed before the division: -31 + 17 = -14
x2 = -14112
The fraction: 14112 simplifies by the common factor: 14 into the new fraction: 18
x2 = -18
A trinomial with roots x1 and x2 is a·(x -x1)·(x -x2); bringing the coefficient into the brackets: 56·(x + 18)·(x + 37) = (7x + 3)·(8x + 1)
▶Factors found: (7x + 3)·(8x + 1)