factor 5k^2-18k+9
Let's factor in ℝ: 5k2 -18k + 9
Given the quadratic form ak2 + bk + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 5, b = -18 and c = 9
Δ = (-18)2 -4·5·9
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-18)2 = (-18)·(-18) = 324■Multiplications are done before additions and subtractions: 4·5 = 20
Δ = 324 -20·9
ⓘ Multiplications are done before additions and subtractions: 20·9 = 180
Δ = 324 -180
ⓘ Start from 324 and move back 180 on the number line: 324 -180 = 144
Δ = 144
As Δ > 0, the equation has two roots:
The quadratic formula gives k1 = -b -Δ2a = -(-18) -1442·5
k1 = 18 -1442·5
ⓘ The square root of a number is the positive number whose square is that number: 144 = 12; 122 = 144
ⅰ 2·5 = 10
k1 = 18 -1210
ⓘ The numerator and the denominator are computed before the division: 18 -12 = 6
k1 = 610
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 610 = 3·25·2 = 35
k1 = 35
The quadratic formula gives k2 = -b + Δ2a = -(-18) + 1442·5
k2 = 18 + 1442·5
ⓘ The square root of a number is the positive number whose square is that number: 144 = 12; 122 = 144
ⅰ 2·5 = 10
k2 = 18 + 1210
ⓘ The numerator and the denominator are computed before the division: 18 + 12 = 30
k2 = 3010
ⓘ We simplify the fraction by dividing the numerator and the denominator by 10, their greatest common divisor: 3010 = 3
k2 = 3
A trinomial with roots k1 and k2 is a·(k -k1)·(k -k2); bringing the coefficient into the brackets: 5·(k -3)·(k -35) = (k -3)·(5k -3)
▶Factors found: (k -3)·(5k -3)