factor -36a^2+9a^4
1) Let's factor in ℝ: -36a2 + 9a4
We factor out 9, the greatest common divisor of the coefficients: -36a2 + 9a4 = 9·(-4a2 + a4)
For -4a2 + a4, we recognize a difference of two squares: (a2)2 -(2a)2. Apply A2 -B2 = (A -B)·(A + B), with A = a2 and B = 2a
You can write the expression: -4a2 + a4 in factored form: (a2 -2a)·(a2 + 2a)
2) Let's factorize in ℝ: (a2 -2a)·(a2 + 2a)
⇥2.1) Let's factor in ℝ: (a2 -2a)
⇥You can factorize this expression into: a·(a -2)
▷The factor (a2 -2a) factors as: a·(a -2)
⇥2.2) Let's factor in ℝ: (a2 + 2a)
⇥You can factorize this expression into: a·(a + 2)
▷The factor (a2 + 2a) factors as: a·(a + 2)
3) Let's replace each factor by its factorization: a·(a -2)·a·(a + 2)
ⓘ Multiplying powers with the same base adds the exponents: a·a = a2
a2·(a -2)·(a + 2)
ⓘ Factor out the common factor a2
▶Factored expression:   9a2·(a + 2)·(a -2)