factor (x+2)/(x^2-3x-10)
1) Let's factorize in ℝ: x + 2x2 -3x -10
We factorize the numerator and the denominator by looking for their roots; those of the denominator will be forbidden values
2) Let's factorize the denominator: x2 -3x -10
Given the quadratic form ax2 + bx + c, you can calculate the discriminant: Δ = b2 -4ac. Here a = 1, b = -3 and c = -10
Δ = (-3)2 -4·1·(-10)
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-3)2 = (-3)·(-3) = 9
Δ = 9 -4·(-10)
ⓘ Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: -4·(-10) = 40
Δ = 9 + 40
ⓘ Start from 9 and move forward 40 on the number line: 9 + 40 = 49
Δ = 49
Since Δ > 0, the equation has two roots:
The quadratic formula gives x1 = -b -Δ2a = -(-3) -492·1
x1 = 3 -492
ⓘ The square root of a number is the positive number whose square is that number: 49 = 7; 72 = 49
x1 = 3 -72
ⓘ The numerator and the denominator are computed before the division: 3 -7 = -4
x1 = -42
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: -42 = -2
x1 = -2
The quadratic formula gives x2 = -b + Δ2a = -(-3) + 492·1
x2 = 3 + 492
ⓘ The square root of a number is the positive number whose square is that number: 49 = 7; 72 = 49
x2 = 3 + 72
ⓘ The numerator and the denominator are computed before the division: 3 + 7 = 10
x2 = 102
ⓘ We simplify the fraction by dividing the numerator and the denominator by 2, their greatest common divisor: 102 = 5
x2 = 5
▷The denominator x2 -3x -10 factors as: (x + 2)·(x -5)
The roots of the denominator are the forbidden values: x ∈ ℝ \ { -2, 5 }
3) Let's replace the numerator and the denominator by their factorizations: x + 2(x + 2)·(x -5)
ⓘ The original denominator must remain nonzero. The fraction is simplified by dividing the numerator and the denominator by their common factor x + 2: x + 2(x + 2)·(x -5) = 1x -5
▶Factors identified: 1x -5