factor x^3-3x^2-8x-10
1) Let's factor in ℝ: x3 -3x2 -8x -10
⇥1.1) Let's start with the obvious candidate: x = 5
⇥Let's compute the value of: 53 -3·52 -8·5 -10
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 53 = 5·5·5 = 125, 52 = 5·5 = 25■Multiplications are done before additions and subtractions: 8·5 = 40
⇥ 125 -3·25 -40 -10
⇥ⓘ Multiplications are done before additions and subtractions: 3·25 = 3·(20 + 5) = 3·20 + 3·5 = 60 + 15 = 75
⇥ 125 -75 -40 -10
⇥ⓘ Start from 125 and move back 75 on the number line: 125 -75 = 50
⇥ 50 -40 -10
⇥ⓘ Start from 50 and move back 40 on the number line: 50 -40 = 10
⇥ 10 -10
⇥ⓘ Start from 10 and move back 10 on the number line, down to zero: 10 -10 = 0
⇥ 0
⇥Root found: x = 5
⇥1.2) Let's start the euclidean division of (x3 -3x2 -8x -10) by (x -5)
⇥
Current expressionDivide
leading terms
QuotientQuotient × divisorRemainder after subtracting
x3 -3x2 -8x -10x3xx2x2·(x -5) = x3 -5x2(x3 -3x2 -8x -10) -(x3 -5x2) = 2x2 -8x -10
2x2 -8x -102x2x2x2x·(x -5) = 2x2 -10x(2x2 -8x -10) -(2x2 -10x) = 2x -10
2x -102xx22·(x -5) = 2x -10(2x -10) -(2x -10) = 0
⇥Therefore, the result of the euclidean division is: x2 + 2x + 2
ⅰ x3 -3x2 -8x -10 = (x -5)·(x2 + 2x + 2)
▶Factored expression:   (x -5)·(x2 + 2x + 2)