factor x^3+2x^2-36x-72
1) Let's factorize in ℝ: x3 + 2x2 -36x -72
⇥1.1) Try the obvious solution first: x = -2
⇥Let's evaluate the value of: (-2)3 + 2·(-2)2 -36·(-2) -72
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-2)3 = (-2)·(-2)·(-2) = -8, (-2)2 = (-2)·(-2) = 4■Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: -36·(-2) = 36·2 = (30 + 6)·2 = 30·2 + 6·2 = 60 + 12 = 72
⇥ -8 + 2·4 + 72 -72
⇥ⓘ Multiplications are done before additions and subtractions: 2·4 = 8■Start from 72 and move back 72 on the number line, down to zero: 72 -72 = 0
⇥ -8 + 8 + 0
⇥ⓘ Adding 0 changes nothing: 8 + 0 = 8■Start from -8 and move forward 8 on the number line, up to zero: -8 + 8 = 0
⇥ 0
⇥Root found: x = -2
⇥1.2) Compute the quotient and remainder of (x3 + 2x2 -36x -72) ÷ (x + 2)
⇥
Expression in progressDivide
leading terms
QuotientQuotient × divisorRemainder after subtracting
x3 + 2x2 -36x -72x3xx2x2·(x + 2) = x3 + 2x2(x3 + 2x2 -36x -72) -(x3 + 2x2) = -36x -72
-36x -72-36xx-36-36·(x + 2) = -36x -72(-36x -72) -(-36x -72) = 0
⇥So the result of the euclidean division is: x2 -36
⇥1.3) Let's factorize in ℝ: (x2 -36)
⇥For x2 -36, we recognize a difference of two squares: x2 -62. Apply a2 -b2 = (a -b)·(a + b), with a = x and b = 6
▷The factor (x2 -36) factors as: (x + 6)·(x -6)
▶Factored expression:   (x + 2)·(x + 6)·(x -6)