factor x^4-6x^2-2x+4
1) Let's factor in ℝ: x4 -6x2 -2x + 4
⇥1.1) Try the obvious solution first: x = -2
⇥Let's evaluate the value of: (-2)4 -6·(-2)2 -2·(-2) + 4
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-2)4 = (-2)·(-2)·(-2)·(-2) = 16, (-2)2 = (-2)·(-2) = 4■Multiplications are done before additions and subtractions. Two minus signs cancel out, the product of two negative numbers is positive: -2·(-2) = 4
⇥ 16 -6·4 + 4 + 4
⇥ⓘ Multiplications are done before additions and subtractions: 6·4 = 24
⇥ 16 -24 + 4 + 4
⇥ⓘ Start from 16 and move back 24 on the number line, going below zero: 16 -24 = -8
⇥ -8 + 4 + 4
⇥ⓘ Start from -8 and move forward 4 on the number line, getting closer to zero: -8 + 4 = -4
⇥ -4 + 4
⇥ⓘ Start from -4 and move forward 4 on the number line, up to zero: -4 + 4 = 0
⇥ 0
⇥Root found: x = -2
⇥1.2) Perform polynomial long division of (x4 -6x2 -2x + 4) by (x + 2)
⇥
Current expressionDivide
leading terms
QuotientQuotient × divisorRemainder after subtracting
x4 -6x2 -2x + 4x4xx3x3·(x + 2) = x4 + 2x3(x4 -6x2 -2x + 4) -(x4 + 2x3) = -2x3 -6x2 -2x + 4
-2x3 -6x2 -2x + 4-2x3x-2x2-2x2·(x + 2) = -2x3 -4x2(-2x3 -6x2 -2x + 4) -(-2x3 -4x2) = -2x2 -2x + 4
-2x2 -2x + 4-2x2x-2x-2x·(x + 2) = -2x2 -4x(-2x2 -2x + 4) -(-2x2 -4x) = 2x + 4
2x + 42xx22·(x + 2) = 2x + 4(2x + 4) -(2x + 4) = 0
⇥Therefore, the result of the euclidean division is: x3 -2x2 -2x + 2
ⅰ x4 -6x2 -2x + 4 = (x + 2)·(x3 -2x2 -2x + 2)
▶Factored expression:   (x + 2)·(x3 -2x2 -2x + 2)