We add the definition: g(x) = x2 + 5x Using stored definitions, replace g(-2) + 2 with (-2)2 + 5×-2 + 2 Let's evaluate: (-2)2 + 5×-2 + 2 ℹ(-2)2 = 4‖5×-2 = -10 4 -10 + 2 ℹ4 -10 = -6 -6 + 2 ▷Result: -4