inflection f(x)=x^4-54x^2+1
1) For x4 -54x2 + 1 on ℝ, find where the second derivative is zero and changes sign
⇥1.1) Let's differentiate: ddx(x4 -54x2 + 1)
⇥ⓘ The derivative of a sum is the sum of the derivatives: ddx(x4 -54x2 + 1) = ddx(x4) + ddx(-54x2) + 0
⇥ ddx(x4) + ddx(-54x2) + 0
⇥ⓘ The derivative of x^n is n*x^(n-1): ddx(x4) = 4x3, ddx(x2) = 2x■Adding 0 changes nothing: ddx(-54x2) + 0 = ddx(-54x2)■A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(-54x2) = -54·ddx(x2)
⇥ 4x3 -54·2x
⇥ⓘ Multiplications are done before additions and subtractions: 54·2 = (50 + 4)·2 = 50·2 + 4·2 = 100 + 8 = 108
⇥ 4x3 -108x
The first derivative is 4x3 -108x
⇥1.2) Let's differentiate: ddx(4x3 -108x)
⇥ⓘ The derivative of a sum is the sum of the derivatives: ddx(4x3 -108x) = ddx(4x3) + ddx(-108x)
⇥ ddx(4x3) + ddx(-108x)
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(4x3) = 4·ddx(x3), ddx(-108x) = -108■The derivative of x^n is n*x^(n-1): ddx(x3) = 3x2
⇥ 4·3x2 -108
⇥ⓘ Multiplications are done before additions and subtractions: 4·3 = 12
⇥ 12x2 -108
⇥We factor out 12, the greatest common divisor of the coefficients: 12x2 -108 = 12·(x2 -9)
⇥Factor identified: x2 -9
The second derivative is 12·(x2 -9)
⇥1.3) Let's solve in ℝ: 12·(x2 -9) = 0
⇥We simplify the expression by 12
⇥⇥Let's solve in ℝ: x2 -9 = 0
⇥⇥The two numbers whose square is 9 are -3 and 3
⇥⇥Solutions obtained: x = { -3, 3 }
⇥1.4) Let's differentiate: ddx(12·(x2 -9))
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(12·(x2 -9)) = 12·ddx(x2 -9)■The derivative of a sum is the sum of the derivatives: ddx(x2 -9) = ddx(x2) + 0
⇥ 12·(ddx(x2) + 0)
⇥ⓘ Adding 0 changes nothing: ddx(x2) + 0 = ddx(x2)■The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
⇥ 12·2x
⇥ⅰ 12·2 = (10 + 2)·2 = 10·2 + 2·2 = 20 + 4 = 24
⇥ 24x
At x = -3, the zero of the second derivative has order 1: this order is odd, so the concavity changes
Near -3, the second derivative is positive on the left and negative on the right: the curve changes from concave up to concave down
⇥ (-3)4 -54·(-3)2 + 1
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: (-3)4 = (-3)·(-3)·(-3)·(-3) = 81, (-3)2 = (-3)·(-3) = 9
⇥ 81 -54·9 + 1
⇥ⓘ Multiplications are done before additions and subtractions: 54·9 = (50 + 4)·9 = 50·9 + 4·9 = 450 + 36 = 486
⇥ 81 -486 + 1
⇥ⓘ Start from 81 and move back 486 on the number line, going below zero: 81 -486 = -405
⇥ -405 + 1
⇥ⓘ Start from -405 and move forward 1 on the number line, getting closer to zero: -405 + 1 = -404
⇥ -404
The y-coordinate is f(-3) = -404
⇥1.5) Let's perform the differentiation: ddx(12·(x2 -9))
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(12·(x2 -9)) = 12·ddx(x2 -9)■The derivative of a sum is the sum of the derivatives: ddx(x2 -9) = ddx(x2) + 0
⇥ 12·(ddx(x2) + 0)
⇥ⓘ Adding 0 changes nothing: ddx(x2) + 0 = ddx(x2)■The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
⇥ 12·2x
⇥ⅰ 12·2 = (10 + 2)·2 = 10·2 + 2·2 = 20 + 4 = 24
⇥ 24x
At x = 3, the zero of the second derivative has order 1: this order is odd, so the concavity changes
Near 3, the second derivative is negative on the left and positive on the right: the curve changes from concave down to concave up
⇥ 34 -54·32 + 1
⇥ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 34 = 3·3·3·3 = 81, 32 = 3·3 = 9
⇥ 81 -54·9 + 1
⇥ⓘ Multiplications are done before additions and subtractions: 54·9 = (50 + 4)·9 = 50·9 + 4·9 = 450 + 36 = 486
⇥ 81 -486 + 1
⇥ⓘ Start from 81 and move back 486 on the number line, going below zero: 81 -486 = -405
⇥ -405 + 1
⇥ⓘ Start from -405 and move forward 1 on the number line, getting closer to zero: -405 + 1 = -404
⇥ -404
The y-coordinate is f(3) = -404
▶Inflection points:   { (-3, -404), (3, -404) }
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