inflection x^5
1) For x5 on ℝ, find where the second derivative is zero and changes sign
⇥1.1) Let's differentiate: ddx(x5)
⇥ⓘ The derivative of x^n is n*x^(n-1): ddx(x5) = 5x4
⇥ 5x4
The first derivative is 5x4
⇥1.2) Let's perform the differentiation: ddx(5x4)
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(5x4) = 5·ddx(x4)■The derivative of x^n is n*x^(n-1): ddx(x4) = 4x3
⇥ 5·4x3
⇥ⅰ 5·4 = 20
⇥ 20x3
The second derivative is 20x3
⇥1.3) Let's solve in ℝ: 20x3 = 0
⇥We simplify the expression by 20
⇥⇥Let's solve in ℝ: x3 = 0
⇥⇥x3 = 0 is equivalent to: x = 0
⇥⇥Solution obtained: x = 0
⇥1.4) Let's perform the differentiation: ddx(20x3)
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(20x3) = 20·ddx(x3)■The derivative of x^n is n*x^(n-1): ddx(x3) = 3x2
⇥ 20·3x2
⇥ⅰ 20·3 = 60
⇥ 60x2
⇥1.5) Let's differentiate: ddx(60x2)
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(60x2) = 60·ddx(x2)■The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
⇥ 60·2x
⇥ⅰ 60·2 = 120
⇥ 120x
⇥1.6) Let's perform the differentiation: ddx(120x)
⇥ⓘ A constant factor stays in front of the derivative, (k*u)' = k*u': ddx(120x) = 120
⇥ 120
At x = 0, the zero of the second derivative has order 3: this order is odd, so the concavity changes
Near 0, the second derivative is negative on the left and positive on the right: the curve changes from concave down to concave up
⇥ 05
⇥ 0
The y-coordinate is f(0) = 0
▶Inflection points:   {(0, 0)}
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