integ(x^2,x,[0,1])
Let's compute the integral: ∫(x2)dx
x33
Let's evaluate over the interval [0, 1]: 133 -033
13 = 103 = 003 = 0
13 + 0
13
The approximate value of: 13 equals:
0.3333
Answer:   13
▷▷Numeric:  0.3333