integral from 0 to 2 of x^6
Let's compute the integral: ∫02x6dx
ⓘ An antiderivative of x^n is x^(n+1)/(n+1), for n ≠ -1: ∫x6dx = x77
▷ x77
Let's evaluate over the interval [0, 2]: 277 -077
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 27 = 2·...·2, 7 times = 128
1287 + 0
ⓘ Adding 0 changes nothing: 1287 + 0 = 1287
▶Integral:   1287
The numeric value of: 1287 equals:
▷ ≈ 18.2857