integral from 0 to 3 of sqrt(5)
Let's integrate: ∫035dx
ⓘ The derivative of 5×x is 5, so 5×x is an antiderivative of 5: ∫5dx = 5×x
▷ 5×x
Let's evaluate over the interval [0, 3]: 3×5 -0×5
ⓘ A product with a zero factor is zero: 0×5 = 0
3×5 + 0
ⓘ Adding 0 changes nothing: 3×5 + 0 = 3×5
▶Integral:   3×5
The numeric value of: 3×5 equals:
3×≈ 2.2361
▷ ≈ 6.7082