integral from 3.5 to 7 of 274000-39200x
1) Let's integrate: ∫3.57(274,000 -39,200x)dx
ⅰ ∫(274,000 -39,200x)dx = ∫274,000dx -∫39,200xdx
∫274,000dx -∫39,200xdx
ⓘ The derivative of 274,000x is 274,000, so 274,000x is an antiderivative of 274,000: ∫274,000dx = 274,000x■A constant factor stays in front of the integral. An antiderivative of x^n is x^(n+1)/(n+1), for n ≠ -1: -∫39,200xdx = -39,200·x22
274,000x -39,200·x22
ⓘ Multiplying a fraction by a number multiplies its numerator: 39,200·x22 = 39,200x22■A fraction is simplified by dividing the numerator and the denominator by the same number: -39,200x22 = -19,600x2
274,000x -19,600x2
You can write the expression in factored form: x·(274,000 -19,600x)
Let's factor in ℝ: (274,000 -19,600x)
We factor out 400, the greatest common divisor of the coefficients: 274,000 -19,600x = 400·(685 -49x)
Factor found: 685 -49x
▷400x·(685 -49x)
2) Let's evaluate over the interval [3.5, 7]: 400·7·(685 -49·7) -400·3.5·(685 -49·3.5)
ⓘ Multiplications are done before additions and subtractions: 49·7 = (40 + 9)·7 = 40·7 + 9·7 = 280 + 63 = 343, 400·7 = 2800■Multiplications are done before additions and subtractions. Multiply without the decimal points, then put the point back by counting the decimals of both factors: 49·3.5 = 49·3510 = 171510 = 171.5, 400·3.5 = 400·3510 = 14,00010 = 1400
2800·(685 -343) -1400·(685 -171.5)
ⓘ Parentheses are computed first: 685 -343 = 342, 685 -171.5 = 513.5
2800·342 -1400·513.5
ⓘ Multiplications are done before additions and subtractions: 2800·342 = 2800·(300 + 40 + 2) = 2800·300 + 2800·40 + 2800·2 = 840,000 + 112,000 + 5600 = 957,600■Multiplications are done before additions and subtractions. Multiply without the decimal points, then put the point back by counting the decimals of both factors: 1400·513.5 = 1400·513510 = 7,189,00010 = 718,900
957,600 -718,900
ⓘ Start from 957,600 and move back 718,900 on the number line: 957,600 -718,900 = 238,700
▶Integral:   238,700