integral of (10)/((25x^2+1)^2)
Let's integrate: ∫(10(25x2 + 1)2)dx
The denominator 25x2 + 1 is strictly positive on ℝ. Let u = 5x, so du = 5dx
The quotient rule and the derivative of atan give (u1 + u2 + atan(u))' = 2·1(1 + u2)2: an antiderivative of 1(1 + u2)2 is u1 + u2 + atan(u)2
Apply the factor 1, then substitute u back: 5x1 + (5x)2 + atan(5x)
5x1 + 52·x2 + atan(5x)
5x1 + 25x2 + atan(5x)
▶Indefinite integrals are defined up to an additive constant C, so this yields: 5x25x2 + 1 + atan(5x) + C