integral of (3x)^2
Before integrating, let's calculate: (3x)2
ⓘ The power of a product is the product of the powers: (3x)2 = 32·x2
32·x2
ⓘ Powers are computed before multiplications, additions and subtractions. An integer power is a repeated product: 32 = 3·3 = 9
9x2
Let's compute the integral: ∫9x2dx
ⓘ A constant factor stays in front of the integral. An antiderivative of x^n is x^(n+1)/(n+1), for n ≠ -1: ∫9x2dx = 9·x33
9·x33
ⓘ Multiplying a fraction by a number multiplies its numerator: 9·x33 = 9x33■A fraction is simplified by dividing the numerator and the denominator by the same number: 9x33 = 3x3
3x3
▶Indefinite integrals are defined up to an additive constant C, so this yields: 3x3 + C