integral of (5x)/(cos^2(x^2))
Let's compute the integral: ∫5xcos(x2)2dx
For the math expression: 5xcos(x2)2, since (tan(a))' = a'/cos(a)^2, we try differentiating tan(x2)
Let's differentiate: ddx(tan(x2))
We differentiate using: ddx(tan(f)) = ddx(f)·1cos(f)2 (where f = x2)
ⓘ The derivative of tan(x) is 1/cos(x)^2: ddx(tan(x2)) = ddx(x2)·1cos(x2)2
ddx(x2)·1cos(x2)2
ⓘ The derivative of x^n is n*x^(n-1): ddx(x2) = 2x
2xcos(x2)2
You observe that the computed derivative and the original math expression are the same, except for a coefficient. So the integral is:
ⓘ The derivative of 52·tan(x2) is 5xcos(x2)2, so 52·tan(x2) is an antiderivative of 5xcos(x2)2: ∫5xcos(x2)2dx = 52·tan(x2)
52·tan(x2)
ⓘ Multiplying a fraction by a term multiplies its numerator: 52·tan(x2) = 5·tan(x2)2
5·tan(x2)2
▶Indefinite integrals are defined up to an additive constant C, so this yields: 5·tan(x2)2 + C