integrate 1/sqrt(x)
Let's integrate: ∫(1x)dx
We attempt to reverse an integration: starting from 1x and (an)' = na(n -1), we differentiate using ^(m+1)
Let's differentiate: (x(-12 + 1))'
(x(-1 + 22))'
(x)'
12x
The computed derivative matches the original math expression up to a constant factor. Therefore, the integral is:
2·1x-12
2x
Indefinite integrals are defined up to an additive constant C, so this yields: 2x + C
Answer:   2x + C, with C being any constant