integrate 1/x^2
Let's integrate: ∫(1x2)dx
For the math expression: 1x2, we know the derivative formula: (an)' = na(n -1), so we try differentiating with ^(m+1)
Let's differentiate: (x(-2 + 1))'
(x-1)'
Apply the differentiation rule: (fn)' = n·(f)'·f(n -1) with f = x
-1·x-2
-x-2
1-x2
-1x2
The computed derivative matches the original math expression up to a constant factor. Therefore, the integral is:
-1·1x
-1x
Indefinite integrals are defined up to an additive constant C, so this yields: -1x + C
Answer:   -1x + C, where C is a constant