integrate 1/x^2 — step-by-step solution

Let's compute the integral:

\int \frac{1}{x^{2}} d x

ⓘ An antiderivative of x^n is x^(n+1)/(n+1), for n ≠ -1:

\int \frac{1}{x^{2}} d x

\int x^{-2} d x

- x^{-1}

- \frac{1}{x}

- \frac{1}{x}

▶Indefinite integrals are defined up to an additive constant C, so this yields:

- \frac{1}{x} + C